Forces and Motion | Physics Mdcat | Practice Mcqs | mosaicbro.com

Forces and Motion | Physics Mdcat | Practice Mcqs

7 of 50 questions (Page 1 of 8)

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1 Distance covered by a freely falling body in 2 seconds will be?
Correct Answer: B
Explanation: Using the equation of motion for free fall, distance = 0.5 * g * t², where g = 9.8 m/s² and t = 2 s. The calculation yields 19.6 m.
2 1st law of motion gives definition of?
Correct Answer: C
Explanation: Newton's first law defines force as the agent that changes the state of rest or motion of a body.
3 A 7.0 Kg ball experiences a net force of 7.0 N. What will be its acceleration?
Correct Answer: C
Explanation: Using Newton's second law, F = ma, acceleration a = F/m = 7.0 N / 7.0 kg = 1 m/s².
4 An object with a constant speed?
Correct Answer: B
Explanation: An object with constant speed might be accelerated if its direction changes, as in uniform circular motion.
5 The ratio of distance to magnitude of displacement when a body covers a semicircle is?
Correct Answer: A
Explanation: For a semicircle, distance is πR and displacement is 2R. The ratio is πR / 2R = π/2.
6 The distance travelled by a body dropped from the top of a tower is proportional to?
Correct Answer: D
Explanation: The distance fallen under gravity is given by d = 0.5 * g * t², which is proportional to the square of time.
7 Which pair contains one scalar and one vector?
Correct Answer: C
Explanation: Force is a vector quantity, while kinetic energy (K.E) is a scalar quantity.
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